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Continuous Functions

 
 
Definition. A function f is continuous at x = a if and only if

If a function f is continuous at x = a then we must have the following three conditions.

  1. f(a) is defined; in other words, a is in the domain of f.
  2. The limit

    must exist.

  3. The two numbers in 1. and 2., f(a) and L, must be equal


Theorem A. A polynomial is continuous at each real number. A rational function is continuous at each point of its domain.

Theorem B. Suppose that f and g are functions which are continuous at the point x = a and suppose that k is a constant. Then

  1. The product k f is continuous at x = a.
  2. The sum f + g is continuous at x = a.
  3. The difference f - g is continuous at x = a.
  4. The product f g is continuous at x = a.
  5. The quotient f / g is continuous at x = a provided that g(a) is not zero.

Theorem C. Suppose that g is a function which is continuous at x = a and suppose that f is a function which is continuous at x = g(a) then the composition of f and g is continuous at x = a.


Examples:

Example. Consider the function

egin{displaymath}f(x) = left{ egin{array}{rll}
x^3 + 2& mbox{if  < 2...
...x = 2
x^2 + 6 & mbox{if  > 2;.
end{array}
ight.end{displaymath}


 

The details are left to the reader to see

egin{displaymath}lim_{x
ightarrow 2-} f(x) = lim_{x
ightarrow 2-} x^3 + 2 = 10,end{displaymath}


 

and

egin{displaymath}lim_{x
ightarrow 2+} f(x) = lim_{x
ightarrow 2+} x^2 + 6 = 10.end{displaymath}


 

So we have

egin{displaymath}lim_{x
ightarrow 2} f(x) = 10.end{displaymath}


 

Since f(2) = 5, then f(x) is not continuous at 2.


Exercise 1. Find A which makes the function

egin{displaymath}f(x) = left{ egin{array}{rll}
x^2 - 2& mbox{if  < 1
A x - 4 & mbox{if $1 leq x
end{array}
ight.end{displaymath}


 

continuous at x=1.

We have

egin{displaymath}lim_{x
ightarrow 1-} f(x) = lim_{x
ightarrow 1-} x^2 - 2 = -1,end{displaymath}


 

and

egin{displaymath}lim_{x
ightarrow 1+} f(x) = lim_{x
ightarrow 1+} A x -4 = A - 4.end{displaymath}


 

So f(x) is continuous at 1 iff

egin{displaymath}A - 4 = -1 ;;mbox{or equivalently if};; A = 3;.end{displaymath}


 





The graphic shows a jump discontinuity.

 


This is an Essential Discontinuity:

 

 


 


 


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